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Discussion

Two solutions S1 and S2 contain whisky and soda in the ratio 2 : 5 and 6 : 7 respectively. In what ratio these solutions be mixed to get a new solution S3,  containing whisky and soda in the ratio 5 : 8 ?

  • A.7:9
  • B.21:5
  • C.23:6
  • D.6:23

Answer: A

Let the amount taken from S1 be 7x
And amount taken from S2 be 13y

(2x + 6y)/(5x + 7y) = 5/8
16x + 48y = 25x + 35y
9x = 13y
x/y = 13/9

Actual ratios of amounts 
               = 7x/13y
               = (7/13) * (13/9)
               = 7/9

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