Top

Discussion

A transistor has a power rating of 8 W for a case temperature of 25°C. If derating factor is 30 mW/°C, the power rating for 55°C, case temperature is

  • A.8 W
  • B.
    7.5 W
  • C.7.1 W
  • D.6.8 W

Answer: C

Power rating = 8 - (55 - 25)(30 x 10-3) = 7.1 W.

No comment is present. Be the first to comment.
Loading…

Post your comment