The diffrence between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m,then its area is:
Answer: D
We have (l-b) = 23 and 2(l+b) = 206 or (l+b) = 103
Solving the two equatoins, we get l = 63 and b = 40
∴(l×b) = (63×40)m⊃2; = 2520 m⊃2;