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If \(x/y = 6/5\), the value of \(\frac{x^2+y^2}{x^2-y^2}\) is:

  • A.11/61
  • B.61/11
  • C.31/1
  • D.1/31

Answer: B

We can let x=6 and y=5.

Substitute these values into the expression:

\(\frac{6^2+5^2}{6^2-5^2} = \frac{36+25}{36-25} = \frac{61}{11}\).

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