A number is first increased by 20% and then decreased by 10%. Find the net percentage change.
Answer: C
We can use the successive percentage change formula: \(A + B + \frac{AB}{100}\).
Here, A = +20 (increase) and B = -10 (decrease).
Net change = \(20 + (-10) + \frac{20 \times (-10)}{100}\)
= \(10 - \frac{200}{100} = 10 - 2 = 8\)%.
Since the result is positive, it is an 8% increase.