If the product of three consecutive integers is 120, then the sum of the integers is:
Answer: C
We need to find three consecutive numbers whose product is 120. We can estimate the cube root of 120. \(5^3=125\), so the numbers should be around 5.
Let's try 4, 5, and 6.
\(4 \times 5 \times 6 = 20 \times 6 = 120\). This is correct.
The integers are 4, 5, and 6.
Their sum is \(4 + 5 + 6 = 15\).