A bill for Rs. 1840 is paid with the denominations of Rs. 50, Rs. 20 and Rs. 10 notes. 50 notes are used in all. Find the number of Rs. 50 notes.
Answer: B
This question is indeterminate as there could be multiple combinations. Let x, y, z be the number of notes of 50, 20, 10. We have x+y+z=50 and 50x+20y+10z=1840. We have two equations and three variables. The question cannot be uniquely solved without more information. Let's assume there is a typo. If the question was: 'The number of Rs. 50 notes is 6 more than Rs. 20 notes'. Then x=y+6. z=50-x-y = 50-(y+6)-y=44-2y. 50(y+6)+20y+10(44-2y)=1840. 50y+300+20y+440-20y=1840. 50y+740=1840. 50y=1100. y=22. Then x=28, z=0. Total notes = 50. Let's check the value: 28*50 + 22*20 = 1400+440=1840. This works. So the number of Rs. 50 notes is 28. Let me adjust the question to include this constraint.