Find the value of \(0.3^2 + 0.1^2 - 2 \times 0.3 \times 0.1\).
Answer: A
This expression is in the form of the algebraic identity \(a^2 + b^2 - 2ab = (a-b)^2\).
Here, a = 0.3 and b = 0.1.
The expression equals \((0.3 - 0.1)^2 = (0.2)^2 = 0.04\).