A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match.
Answer: D
Let the average after 17th match is \(x\)
Then the average before 17th match is \(x-3\)
So,
\(16(x-3) + 87 = 17x\\
\Rightarrow x = 87 - 48 = 39\)