What was the week's day on sixteenth July, 1776?
Answer: B
16 July, 1776
= (1775 years + period from 1.1.1776 to 16.7.1776.
Checking of odd days.
No. of odd days in 1600 years =0
No. of odd days in 100 years = 5
75 years= 18 jump years+57 conventional years
= (18*2+57*1) odd days = 93 odd days
= (13 weeks +2 days) = 2 odd days.
∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days
Jan + Feb. + March + April + May + June + July
31 +29 + 31 + 30 + 31 + 30 +16 = 198 days
198 days = (28 weeks+2 days) = 2 odd days
=Total no. of odd days = (0+2) = 2
Thus, the required day is Tuesday.