What was the week's day on seventeenth June, 1988?
Answer: D
17th June, 1998= (1997 year Period structure 1.1.1998 to 17.6.1998)
Odd days in 1600 year=0.
Odd days in 300 year = (5*3) =1.
97 year has 24 jump year +73 standard years.
= 24*2 + 73*1
= 48 + 73
= 121 odd days
= 17 weeks + 2 odd days = 2 odd days
= 2 odd days.
∴ 1998 years have (0+1+2) = 3 odd days
Jan to June = (31+29+31+30+31)
= 152 days
Add 17 days of June.
= 152 + 17
= 169 days
= 24 weeks + 1 days
= 1 odd day.
∴ Total number of odd day = 3 + 1 = 4 odd days.
Hence 17.06.1998 was Thursday.