A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?
Answer: B
[(100 x 35) + (200 x 5)]men can finish the work in 1 day
Therefore, 4500 men can finish the work in 1 day. 100 men can finish it in 4500/100= 45 days.
This is 5 days behind Schedule