What is the slope of a line that is perpendicular to the line y = -3x + 4?
Answer: C
The given line is in the form y = mx + c, so its slope (m₁) is -3.
If two lines are perpendicular, the product of their slopes is -1. Let the slope of the perpendicular line be m₂.
m₁ × m₂ = -1
-3 × m₂ = -1
m₂ = \(\frac{-1}{-3} = \frac{1}{3}\).