The points A(1, 5), B(2, 3) and C(-2, 11) are:
Answer: A
Three points are collinear if the slope between any two pairs of points is the same.
Slope of AB = \(\frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 5}{2 - 1} = \frac{-2}{1} = -2\).
Slope of BC = \(\frac{y_3 - y_2}{x_3 - x_2} = \frac{11 - 3}{-2 - 2} = \frac{8}{-4} = -2\).
Since the slope of AB is equal to the slope of BC, the points A, B, and C lie on the same straight line and are collinear.