The equation of the line whose slope is -4/3 and which passes through (-3, 6) is:
Answer: A
Using the point-slope form y - y₁ = m(x - x₁):
y - 6 = -4/3 (x - (-3))
y - 6 = -4/3 (x + 3)
3(y - 6) = -4(x + 3)
3y - 18 = -4x - 12
4x + 3y = -12 + 18
4x + 3y = 6