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The access time of a word in 4 MB main memory is 100 ms. The access time of a word in a 32 kb data cache memory is 10 ns. The average data cache bit ratio is 0.95. The efficiency of memory access time is

  • A.9.5 ns
  • B.
    14.5 ns
  • C.20 ns
  • D.95 ns

Answer: B

Access time = 0.95 x 10 + 0.05 x 100.

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