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Decimal number 46 in excess 3 code =

  • A.1000 1001
  • B.
    0111 1001
  • C.0111 1111
  • D.1000 1111

Answer: B

Decimal 46 in excess 3 code = 46 + 33 = 79 in decimal = 0111 1001 in 4 bit binary.

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