What is the remainder when the product \(121 \times 122 \times 124\) is divided by 7?
Answer: A
We find the remainder of each number when divided by 7 individually and then multiply the remainders.
Remainder of \(121 \div 7\) is 2 (since \(121 = 17 \times 7 + 2\)).
Remainder of \(122 \div 7\) is 3 (since \(122 = 17 \times 7 + 3\)).
Remainder of \(124 \div 7\) is 5 (since \(124 = 17 \times 7 + 5\)).
The remainder of the overall product is the remainder of \((2 \times 3 \times 5) \div 7\).
\(2 \times 3 \times 5 = 30\).
Now, we find the remainder of \(30 \div 7\).
\(30 = 4 \times 7 + 2\).
The remainder is 2.