What is the remainder when \((29^{29} + 29)\) is divided by 30?
Answer: C
Let's use the property of remainders. We can find the remainder of each part separately. First part: \(29^{29} \div 30\). We can write 29 as \(30-1\). So we need the remainder of \((30-1)^{29} \div 30\). The remainder is \((-1)^{29} = -1\). Second part: \(29 \div 30\). The remainder is 29. Now, we add the remainders: \(-1 + 29 = 28\). The final remainder is 28.