What is the remainder when \(143^3\) is divided by 11?
Answer: A
First, let's find the remainder when the base, 143, is divided by 11. Sum of alternate digits: (3+1) - 4 = 0. Since the difference is 0, 143 is divisible by 11. The remainder is 0. Therefore, \(143^3\) will also be divisible by 11, and the remainder will be 0.