What is the unit digit of \(32^{32}\)?
Answer: C
To find the unit digit of \(32^{32}\), we only need to consider the unit digit of the base, which is 2. So the problem is to find the unit digit of \(2^{32}\). The power cycle for 2 is (2, 4, 8, 6), with a length of 4. We need to find the remainder of the power \(32\) when divided by 4. Since 32 is a multiple of 4, the remainder is 0. A remainder of 0 corresponds to the last digit in the cycle, which is 6.