How many trailing zeros are in 1000! ?
Answer: B
We need to find the number of factors of 5 in 1000!. Using Legendre's formula: \(\lfloor 1000/5 \rfloor + \lfloor 1000/25 \rfloor + \lfloor 1000/125 \rfloor + \lfloor 1000/625 \rfloor = 200 + 40 + 8 + 1 = 249\). There are 249 trailing zeros.