What is the unit digit of \(8^{88}\)?
Answer: D
The power cycle for the unit digit of 8 is (8, 4, 2, 6), which has a length of 4. We need to find the remainder of the power \(88\) when divided by 4. Since 88 is a multiple of 4, the remainder is 0. A remainder of 0 corresponds to the last digit in the cycle, which is 6.