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What is the unit digit of \(4!^{2!}\)?

  • A.2
  • B.4
  • C.6
  • D.8

Answer: C

First, evaluate the factorials. \(4! = 24\) and \(2! = 2\). The expression becomes \(24^2\). To find the unit digit, we only need to look at the unit digit of the base, which is 4. The problem is to find the unit digit of \(4^2\), which is 16. The unit digit is 6.

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