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How many diagonals does a pentagon have?

  • A.2
  • B.5
  • C.9
  • D.14

Answer: B

The formula for the number of diagonals in an n-sided polygon is \(\frac{n(n-3)}{2}\).

For a pentagon, n=5.

Number of diagonals = \(\frac{5(5-3)}{2} = \frac{5 \times 2}{2} = 5\).

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