In a \(\triangle ABC\), if AB = 6, BC = 8, and AC = 10, the angle B is:
Answer: C
We check if the side lengths satisfy the Pythagorean theorem. The longest side is AC.
\(AB^2 + BC^2 = 6^2 + 8^2 = 36 + 64 = 100\)
\(AC^2 = 10^2 = 100\)
Since \(AB^2 + BC^2 = AC^2\), the triangle is right-angled, and the right angle is opposite the hypotenuse AC. Therefore, angle B is 90°.