Find the H.C.F. of 54, 288, 360
Answer: A
Using factorization method, \(18 = 2 \times 3^2\) \(288 = 2^5 \times 3^2\) \(360 = 2^3 \times 3^2 \times 5\) So H.C.F. will be minimum term present in all three, i.e. \(2 \times 3^2 = 18\)