Find the H.C.F. of \(\dfrac{2}{3}, \dfrac{4}{6}, \dfrac{8}{27}\)
Answer: A
Formula, \(H.C.F. = \dfrac{H.C.F. of Numerators}{L.C.M. of Denominators}\) So, \(\dfrac{H.C.F. of (2,4,8) }{L.C.M. of (3,6,27)} \\~\\=\dfrac{2}{27}\)