There were two solid spherical balls. Ratio between radius of first ball to that of second ball is 4 : 3. Second ball was cut into two equal halves and the difference between total surface area of first ball and total surface area of a part of second ball is 1424.5 cm⊃2;. Find value of radius of bigger ball ?
Answer: A
Ratio between radius of first ball to that of second ball is 4 : 3.
Let the radius of first ball be '4r' and radius of second ball be '3r'.
When we cut the second ball it become hemisphere.
WKT, Total surface area of sphere = 4π r⊃2;
Total surface area of hemisphere = 3π r⊃2;
As per the question,
4 x (22/7) x (4r)⊃2; - 3 x (22/7) x (3r)⊃2; = 1424.5
(22/7)*r⊃2;[64 - 27] = 1424.5
r⊃2; = [1424.5*7]/[37*22]
r⊃2; = 12.25
r = 3.5 cm
Therefore, radius of bigger ball = 4r = 4(3.5) = 14 cm.