What is the value of \((81)^{-1/4}\) ?
Answer: B
We know that \(81 = 3^4\).
So, \((81)^{-1/4} = (3^4)^{-1/4}\).
Using the rule \((a^m)^n = a^{mn}\), we get \(3^{4 \times (-1/4)} = 3^{-1}\).
\(3^{-1} = \frac{1}{3}\).