Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: A
The required number is the HCF of the differences between the given numbers.
Differences are: \((91 - 43) = 48\), \((183 - 91) = 92\), and \((183 - 43) = 140\).
We need to find the HCF of 48, 92, and 140.
Prime factorization of 48 = \(2^4 \times 3\).
Prime factorization of 92 = \(2^2 \times 23\).
Prime factorization of 140 = \(2^2 \times 5 \times 7\).
The highest common factor is \(2^2 = 4\).