What is the value of 'x' if \(8^x \times 4^3 = 2^{12}\)?
Answer: B
To solve this, express all terms with the same base, which is 2.
\(8 = 2^3\) and \(4 = 2^2\).
The equation becomes \((2^3)^x \times (2^2)^3 = 2^{12}\).
\(2^{3x} \times 2^{6} = 2^{12}\).
\(2^{3x+6} = 2^{12}\).
Equating the exponents: \(3x+6 = 12\).
\(3x = 6\).
\(x = 2\).