The percentage increase in the area of a rectangle, if each of its sides is
increased by 20% is equal to
Answer: D
Let the length of rectangle be \(L\) units and breadth be \(B\) units.
So area of rectangle \(= L \times B\)
As both length and breadth has been increased by 20%
So new length = 1.2\(L\)
New breadth = 1.2\(B\)
New area \(= 1.2L \times 1.2B = 1.44LB\)
Percentage increase in area \(= \frac{1.44LB-LB}{LB} \times 100 = 44\)