Top

Discussion

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in

  • A.144 mins
  • B.140 mins
  • C.136 mins
  • D.132 mins

Answer: A

Let the slower pipe alone fill the tank in x minutes

then faster will fill in x/3 minutes.

Part filled by slower pipe in 1 minute = 1/x

Part filled by faster pipe in 1 minute = 3/x

Part filled by both in 1 minute =

capture5 Dup 2 -30107640

x = 36 × 4 = 144 mins

No comment is present. Be the first to comment.
Loading…

Post your comment