The product of two fractions is 3/4 and their quotient is 6/18. If the denominator of one is 1/3 of the other's numerator, then find the pair of fractions?
Answer: B
Let A = x/y, and B be two fractions
It is given that A×B = 3/4
Therefore x/y × B = 3/4
B = 3y/4x
Therefore, A = x/y and B = 3y/4x
It is given that A/B = (x/y) / (3y/4x) = 6/18
Therefore x/y × 4x/3y = 6 /18
Therefore 4x2/3y2 = 6/18
x2/y2 = 18/(4×18)
Therefore, x2/y2 = 1/4
x/y = 1/2
B = 3y/4x = 3/4 (1/(x/y)) = 3/4 [1/(1/2)] = 6/4
Therefore A = 1/2 and B = 3/2