Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?
Answer: D
Part filled in 4 minutes = 4 | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
15 | 20 | 15 |
Remaining part = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
15 | 15 |
Part filled by B in 1 minute = | 1 |
20 |
![]() |
1 | : | 8 | :: 1 : x |
20 | 15 |
x = | ![]() |
8 | x 1 x 20 | ![]() |
= 10 | 2 | min = 10 min. 40 sec. |
15 | 3 |
The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.