A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
Answer: B
Time taken by one tap to fill half of the tank = 3 hrs.
Part filled by the four taps in 1 hour = | ![]() |
4 x | 1 | ![]() |
= | 2 | . |
6 | 3 |
Remaining part = | ![]() |
1 - | 1 | ![]() |
= | 1 | . |
2 | 2 |
![]() |
2 | : | 1 | :: 1 : x |
3 | 2 |
![]() |
![]() |
1 | x 1 x | 3 | ![]() |
= | 3 | hours i.e., 45 mins. |
2 | 2 | 4 |
So, total time taken = 3 hrs. 45 mins.