What will be the output of the program if the size of pointer is 4-bytes?
#include
int main()
{
printf("%d, %d\n", sizeof(NULL), sizeof(""));
return 0;
}
Answer: C
In TurboC, the output will be 2, 1 because the size of the pointer is 2 bytes in 16-bit platform.
But in Linux, the output will be 4, 1 because the size of the pointer is 4 bytes.
This difference is due to the platform dependency of C compiler.