Three unbiased coins are tossed. What is the probability of getting at least 2 tails?
Answer: B
S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} E = {HTT, THT, TTH, TTT} n(S) = 8 n(E) = 4 P(E) =n(E) / n(S) = 4/8 = 0.5