Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
Answer: C
Let A's age 10 years ago = \(x\) years
Then, B's age 10 years ago = \(2x\) years
\((x + 10) / (2x+ l0) = 3/4 \)
\(\Rightarrow x = 5.\)
So, the total of their present ages = \((x + 10 + 2x + 10) \)
\(= (3x + 20) = 35\) years