A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
Answer: C
Let the age of A = \(A\), B = \(B\) and C = \(C\)
From given,
\(A = 3B\)
4 years ago,
\(A + 4 = 31\)
\(\Rightarrow A=27\)
sub in above \(B\) , we get \(B\) = 9
\(C = 2(27 - 4) + 4 = 46 + 4 = 50 \)
Hence B = 9years and C = 50years.