Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4, what will be the total of their present age?
Answer: C
Let present age of P and Q be \(3x\) and \(4x\) respectively.
\(\left ( 3x-10 \right )=\frac{1}{2}\left ( 4x-10 \right )\)
\(\Rightarrow\) \(6x-20=4x-10\)
\(\Rightarrow\) \(2x=10\)
\(\Rightarrow \) \(x=5\)
Total of their present age is
\(=3x+4x=7x=7×5=35\)