Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
Answer: B
Let the age of younger person is \(x\)
Then elder person age is \((x+6)\)
so 6 years before
\(3(x-6) = (x+16-6)\)
\(\Rightarrow\) \((3x-18) =( x+10)\)
\(\Rightarrow\) \(x=14\)
So other person age is \(x + 16 = 30\)