A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Answer: D
Let the son's present age be x years. Then, man's present age = \((x + 24) years.\)
\(\therefore (x + 24) + 2 = 2(x + 2)\)
\(\Rightarrow x + 26 = 2x + 4\)
\(\Rightarrow x = 22\)