Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
Answer: D
If the number is \(x\)
Then,
\(x + 17 = \dfrac{60}{x}\\
x^2 + 17x - 60 = 0\\
(x + 20)(x - 3) = 0\\
x = 3, -20\\
\text{so } x = 3 (\because 3 \text{ is positive})\)