The sum of the numbers is 264. If the first number be twice the second and third number be one-third of the first, then the second number is:
Answer: C
Let the second number be \(x\). Then, first number \(= 2x\) and third number \(= \dfrac{2x}{3}\)
\(2x + x + \dfrac{2x}{3} = 264\\
\Rightarrow \dfrac{11x}{3} = 264\\
\Rightarrow x = 72\)