The third term of a G.P. is 4. The product of the first five terms is:
Answer: B
Let the first five terms of the G.P. be \(a/r^2, a/r, a, ar, ar^2\). The third term is \(a=4\). The product of these five terms is \((a/r^2) \times (a/r) \times a \times (ar) \times (ar^2) = a^5\). Since a=4, the product is \(4^5 = 1024\).