In a bag, there are coins of \(25 p, 10 p\) and \(5 p\) in the ratio of \(1 : 2 : 3.\) If there is \(Rs. 30\) in all, how many \(5 p\) coins are there?
Answer: C
Let the number of \(25 p, 10 p\) and \(5 p\) coins be \(x, 2x, 3x \) respectively.
Then, sum of there value \(= Rs. (\frac{25x}{100} + \frac{10 \times 2x}{100} + \frac{5 \times 3x}{100}) = Rs. \frac{60x}{100}\)
\(\therefore \frac{60x}{100} = 30 \Leftrightarrow x = \frac{300 \times 100}{60} = 50.\)
Heance, the number of \(5 p\) coins \(= (3 \times 50) = 150.\)