If n(A) = 4 and n(B) = 3, what is the number of possible relations from A to B?
Answer: D
A relation from A to B is a subset of the Cartesian product A × B.
The number of elements in the Cartesian product is n(A × B) = n(A) × n(B) = 4 × 3 = 12.
The number of possible relations is the number of possible subsets of A × B, which is the size of its power set.
Number of relations = \(2^{n(A \times B)} = 2^{12} = 4096\).