What is the square root of \(\left(8+2\sqrt{15}\right)\) ?
Answer: B
\(8+2\sqrt{15}\\= 5+3 + 2 \times\sqrt{5} \times \sqrt{3}\\=(\sqrt{5})^2+(\sqrt{3})^2 + (2 \times\sqrt{5} \times \sqrt{3})\\= (\sqrt{5} +\sqrt{3} )^2\\ \text{Hence, }\sqrt{\left(8+2\sqrt{15}\right)} = \sqrt{(\sqrt{5} +\sqrt{3} )^2} = \sqrt{5} +\sqrt{3}\)